how to solve new york times sudoku

DS in R8C2 [2,5,6] by reduction of 1 in C2 from DS [1,2,5,6] in R8 and DS in R8C3 [2,6] by reduction of [1,5] in C3 from DS [1,2,5,6] in R8. If you cannot logically place a value in a cell then do not place that value in a cell. As a strategy we always start row column scan from digit 1 and continue till digit 9. Now do a parallel scan for 1 in empty cells of column C6 to get the valid cell R1C6 1. How debt-for-climate swaps can help solve low-income countries' fiscal and environmental challenges at the same time About New York Times Games. [2,6] in two cells of C3 forms a Cycle in which the two digits get locked and thus disallows appearance of 2 and 6 in any other empty cell of C3. We'll close here and explore the rest later. In the final solution, 6 can appear in only one of these two cells and in no other cell of the parent bottom right major square or the parent row R8. The online Sudoku NYT puzzle in this game must be solved using logic. R7C4 1 by DSA reduction of 9 from DS [1,9] in R7 -- R7C5 9 by exception in R7. Nevertheless, a distinction between hard, medium and easy Sudoku categories can be made. This will result in a series of valid cells and is a major breakthrough. If a square is incorrect, it will be marked as such. With 3 in R8C6, R8C7 7 by reduction -- R9C7 3 by reduction -- R8C5 6 by reduction -- R9C5 7 by reduction. Observe how the other four empty cells of C6 have been disallowed for 1 by scan for 1 in R2 (disallowing R2C6 for 1), Cycle (1,8) in R6 (disallowing 1 in R6C6), single digit lock in R8 (disallowing R8C6 for 1) and 1 in R9 (disallowing R9C6 for 1). Move around the grid frequently. More Sudoku hard puzzles you may like to solve and learn how to solve. Bur that would have been time-taking. You may perhaps appreciate that, if you have proceeded to form first the possible digit subsets in these four cells and then identified the formation of the Cycle resulting in the valid cell R2C7 8, it would have taken much longer. So we'll next start evaluating 2 or 3 digit possible digit subsets DSs in . Every such easy fill at this stage is a bonus. With this, two more empty cells R8C7 and R8C9 are left for 8 in R8. We are not certain at this point which of the two digits will finally occupy which of the two cells, but taking the two cells together, we are certain that digits [1,8] will certainly occupy these two cells and in no other empty cell in parent zones R6 and left middle square. Description- Self Solving Sudoku- Slice and Dice- Locked Candidates Pointing- Locked Candidates Claiming- Pairs- Locked Candidates Pointing- New York Times S. Play the USA TODAY Sudoku Game. This Cycle immediately causes the breakthrough of R9C1 7 by reduction of [1,5] from DS of [1,5,7] in R9C1 because of the property of locking the four digits inside the Cycled cells only. R5C4 8 by scan for 8 in R4 -- R4C4 6 by exception in C4 -- R4C3 1 by reduction -- R5C3 6 by exception in C3 -- R4C8 4 by exception in R4. Game status shown below. For full enjoyment, avoid looking into any solution as well as the answer. This is a major breakthrough and we'll see its effects in the next stage. This leaves the single cell R2C1 for 3 and the byproduct Cycle of (5,6,7) in the other three empty cells of C1. Hint #1: The word contains three vowels (madness isn't it) one of which, in a different word structure, could be a consonant. This creates Cycle (7,8) in R4. R5C5 7 by DSA reduction of [1,5,8] from DS [1,5,7,8] in C5 -- R6C4 4 by DS reduction of [3,8,9] in C4 from DS [3,4,8,9] in R6. With 4 in R1C8, R5C8 9 by reduction -- R5C7 4 by reduction -- R3C7 9 by exception in C7 -- R3C8 9 by exception in whole game. Fill as many cells as you can by row-column scan. Three digits appear in in the column in only these three cells and nowhere else. If you get stuck, we're here to help with handy hints, as we are every day. R9C7 4 by reduction of 6 from DS [4,6] from R9 -- R9C8 6 by exception in R9 -- R2C8 4 by exception in C8 -- R2C7 3 by exception in whole game. The elimination of four empty cells for 5 in row R2 is shown by red arrows in the Stage 2 solution figure below. An often asked questions is, "What makes a Sudoku puzzle hard?". The joy of discoveries will then all be yours. Cycle reduces possible digit subset for R7C4, R7C6 to [5,7] and with [7] in C6 we get the breakthrough R7C5 5 by reduction of 7 followed by R7C4 7 by exception. 3 Sudoku types . In the process we may get valid cells, but otherwise our lookout is for identifying for a single digit lock by cross scan. SuDoku Archive for October 2012. This creates an opportunity for us to apply advanced technique of double digit scan to get a breakthrough Cycle (1,8). 3 in bottom left major square eliminates R7C1 for 3 and 3 in R1 and R3, eliminate the other two empty cells R1C1 and R3C1 for 3. To be able to solve a Sudoku puzzle in a short time you should know how to use the pencil to trace the board. Cycle (4,7) in R1C4, R1C6 in top middle major square and in R1 by reduction of [8,9] in R1 from possible digit subset [4,7,8,9] in top middle major square -- R1C3 5 by exception in R1 as the only cell left for 5. This is a breakthrough by single digit lock and DSA. In medium or easy Sudoku puzzles, number of filled up cells will be more. With 6 in R1C5, R1C6 2 by reduction -- R1C1 5 by reduction -- R1C4 8 by reduction. Copyright: Atanu Chaudhuri and respective Authors. Before going through the solution solve the puzzle first. Copyright: Atanu Chaudhuri and respective Authors. About New York Times Games. We'll select relatively more promising cells in a row, a column or a 9 cell square (each a zone) to evaluate the smallest length of possible digits in the cells first. The joy of discoveries will then all be yours. Never lose an opportunity for a valid cell hit by row column scan. In this case we get the breakthrough of R9C2 6 by scan for 6 in R7, R8 and C1, 6 in R7 being actually a lock on digit 6. The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games: How to solve Sudoku hard puzzle games full list (includes very hard Sudoku). R4C7 7 by scan for 7 in C8, C9 -- R3C7 9 by reduction of 8 from DS [8,9] in R3 -- R3C9 8 by exception in R3 -- R7C9 9 by reduction -- R7C8 8 by reduction -- R4C9 4 by reduction of 9 from DS [4,9] in R4 -- R4C8 9 by exception -- R9C9 3 by exception in C9. Because of the series of early breakthroughs by advanced digit patterns, the Sudoku hard could be solved rather easily. Observe how three empty cells of R8C1, R8C2, R8C3 are disallowed for digit 8 by the presence of digit 8 in the bottom left major square. The other important property of a parallel digit scan is, it will always be associated with a resultant Cycle in rest of the cells after you get the valid cell. R5C2 5 by exception in C2 -- R6C9 6 by DSA reduction of [1,7] in C9 from DS [1,6,7] in three empty cells of R6 -- R6C4 1 by reduction of 7 from reduced DS [1,7] in R6 -- R6C3 7 by exception in R6 and by reduction. R4C4 4 by scan for 4 in R5, R6, C6 -- R4C6 5 by exception in R4 -- R5C5 7 by scan for 7 in C4, C6. For example, R5C5 2 by DSA reduction of [1,5] in the parent top middle major square itself from the possible digit DS of [1,2,5] in C5. Target is to get two-digit possibilities first. As a strategy we always start row column scan from digit 1 and continue till digit 9. R9C8 2 by scan for 2 in C7 -- R9C3 5 by reduction -- R8C3 2 by reduction -- R9C4 4 by reduction -- R8C4 5 by reduction and exception. This prompts us to look for a valid cell caused by this single digit lock and thus discover the difficult to identify R2C5 5 by parallel digit scan for 5 on empty cells of R2. This Sudoku hard is a challenging puzzle rich with Sudoku digit patterns. Enjoy solving Sudoku hard. Next valid cell R5C6 6 will be shown in next stage. Cycle (1,4,5) formed in R9 in cells R9C4, R9C5, R9C6 -- DS for two empty cells of bottom middle major square [7,8] -- R7C5 8 by reduction of 7 by 7 in C5 -- R7C6 7 by exception in bottom middle major square as the only possible digit left for the only truly empty cell. This is shown by "5" in the two cells. Try free NYT games like the Mini Crossword, Ken Ken, Sudoku & SET plus our new subscriber-only puzzle Spelling Bee. R6C5 3 by scan for 3 in R4, R5, C4 -- R8C6 3 by scan in R7, C4, C5. R7C1 2 by DS reduction of [1,4,6] in C1 from possible digit subset DS [1,2,4,6] in four empty cells of R7. Okay, continuing to identify more possible single digit locks and breakthroughs, with focused intent it doesn't take much to identify a second single digit lock this time on 1 in cells R8C8, R8C9 by scan for 1 in R9, C7. Description- Self Solving Sudoku- Slice and Dice- Locked Candidates Pointing- Triple Subset- Pair- Locked Candidates Claiming- New York Times Sudoku Hard October 21, 2022- Repeat from 19 January 2019- Watch as a Sudoku Classic puzzle is clearly solved step by step.- Stop video, solve the next square, play to check- Each square is solved in order of easy to hard.- Thanks for watching- Share if you like- A more important issue is reminding us to:- Observe the 6 foot rule- Wash our hands- Cough into our elbows- Avoid touching our faces- Wear a better mask- Be glad to get the jabs- Lets keep everyone safe- Cheers#RSOUDREUNSUDOKU#ResolviendoSudoku#SudokuNYT#NYTimes#Sudoku#Puzzle#Puzzles#Solutions Identify Single digit lock on 6 in R7C7, R7C9 by scan for 6 in R8 -- this lock on 6 participates in next valid cell R9C2 6 by scan for 6 in R7 by the lock, 6 in R8 and 6 in C1. Learn more about how to play The New York Times' word games and logic puzzles: Wordle, Spelling Bee, Letterboxed, Tiles, Vertex, and Sudoku. The joy of discoveries will then all be yours. Printable Sudoku New York TimesPrintable Sudoku New York Times - There are many number of ways that to use Printable Sudoku Puzzles. Instead of scanning the promising empty cells of a major square FOR A SINGLE DIGIT, in a double digit scan, the promising empty cells of a major square are scanned for TWO DIGITS TOGETHER. With only 23 filled up, cells this New York Times Sudoku hard puzzle is extra-hard. In medium or easy Sudoku puzzles, number of filled up cells will be more. To start with, R4C9 1 by DSA reduction of [4,9] in R4 from reduced DS [1,4,9] in C9 -- R8C8 1 by single digit lock partner reduction of 1 in R8C9. Identify a second Single digit lock on 5 in R9C5, R9C6 by scan for 5 in R7, C4 -- R9C1 3 by possible digit DS elimination of 5 (because of single digit lock on 5 in R9) from possible digit subset [3,5] in R9C1 (because of [1,4] in C1). For full enjoyment, avoid looking into any solution as well as the answer. There is no metric or measurement to decide for sure that a Sudoku puzzle is hard, or not so hard. Alternately, if R4C3 6, digut [1,7] will appear in eithe of the cells R5C3, R6C3. For example, in this case, after you place 8 in R8C7, it will be easy for you to identify a Cycle of (1,4,5,7) in rest four empty cells without specifically evaluating the possible digit subsets in these cells. It is a fairly hard Sudoku puzzle. Still analyzing this promising neighborhood we detect the possibility of the next breakthrough of R2C1 3 by parallel scan for 3 on empty cells of C1. Both digits 1 and 8 appear together in column C1 but not in any cell of the left major square. As a ball-park figure, any Sudoku puzzle having number of filled up cells 27 and below should be taken as hard or extremely hard. Sunday Los Angeles Times crossword Sunday New York Times crossword Sunday Premier crossword SUDOKU. That means, these two digits light up or affect the intersecting cell R6C1 and reduce its possible digit subset to single digit 3. Enjoy also learning how to solve Sudoku hard in easy steps. These puzzles are Description- Self Solving Sudoku- Slice and Dice- Locked Candidates Pointing- Pair- New York Times Sudoku Hard October 31, 2022- Repeat from 20 August 2017- . With only 24 filled up cells this New York Times Sudoku hard puzzle is fairly hard. We don't bother about other digits appearing in these two cells. We stop in a 9 cell major square when the rest of the empty cells would all have digit possibilities 4, 5 or more. An interesting property of a valid cell by parallel digit scan is, there will always be an associated Cycle after you put the valid digit in its identified cell. AFRAID INCOME LAGOON STYLUS AFFECT DUPLEX. This lock on C9 immediately participates in a row column scan for 3 in R7, lock in R9, 3 in C5 and 3 in C6 to produce unique digit 3 in cell R8C4 -- R8C4 3. To skip the section, click here. With 1 in R7C1, R7C7 5 by reduction -- R9C7 1 by reduction -- R9C4 5 by exception in R9 -- R7C4 9 by exception in whole game. By Jack Tamisiea An elephant's trunk has 40,000 muscles and weighs more than a Burmese python. Reduced DS in two empty cells in C8 is [2,9] -- R2C8 2 by reduction of 9 by R2 -- R2C1 8 by reduction -- R2C7 6 by reduction -- R2C4 3 by exception in R2. This single digit lock has been formed by Cross-scan for 6 in R9, C1 and the Cycle (2,6) formed by DSA in R6C3, R8C3. For easier lower level Sudoku games this systematic method of row column scan should provide a smooth path to the final solution. For full enjoyment, avoid looking into any solution as well as the answer. With 6 in R9C5, R8C2 9 by reduction -- R9C2 6 by reduction. You can include the QR code to any puzzle that is 9x9, for instance, to make it unique. Effect of this critically important single digit lock is reduction of 6 in possible digit subset [1,5,6] to [1,5] in R8C5. This is the hallmark of a truly Sudoku hard puzzle game. Now in addition, a third possible digit subset of [2,6] is formed in R8C3 by DSA reduction of [1,5] from possible digit subset [1,2,5,6] in R8. Enjoy also learning how to solve Sudoku hard in easy steps. If Costner's 1989 baseball movie had featured zombies, it could have been called - FIELD OF "SCREAMS" (Distributed by Tribune Content Agency) This eliminates the cell R6C1 for any of the two digits. We'll end this stage by an important breakthrough in R6C1 7 by parallel digit scan for 7 on empty cells of R6: 7 in C3 debars cell R6C3, 7 in C4 debars 7 in R6C4 and 7 in C6 debars R6C6 for 7 leaving single cell R6C1 for 7. Next identify the advanced technique of Parallel scan for 8 on empty cells of R8: 8 in bottom left major square eliminates R8C1, R8C2, R8C3 for 8 and 8 in C9 eliminates R8C9 for 8 leaving the single cell R8C7 for 8 -- R8C7 8. But by DSA we get the valid cell, R8C2 9 by reduction of [1,5,7] from bottom left major square DS [1,5,7,9] -- R8C3 1 by reduction of [5,7] in R8 from DS [1,5,7] in bottom left major square. By the way, Sudoku hard solution techniques are included with many of the solutions. We are only concerned with the most important fact that digit 5 can appear in only these two cells and NOWHERE ELSE IN THE TWO PARENT ZONES. An effective single digit lock is formed invariably by scan for a digit in a single column or row or more frequently by cross-scan over a row and a column. R6C9 4 by DSA reduction of [7,9] from DS [4,7,9] -- R6C7 7 by reduction -- R5C9 9 by exception in right middle major square -- R3C9 3 by exception in C9. Select a Word Game to learn more: Wordle. R6C2 2 by reduction of 2 by the Cycle (1,6,7) in left middle major square -- R6C6 9 by reduction -- R3C6 8 by reduction -- R2C4 9 by reduction -- R3C1 7 by reduction -- R8C1 5 by reduction -- R8C2 7 by reduction. We can say with 100% certainty that these three digits will be placed in the final solution in only these three cells and nowhere else. By the way, Sudoku hard solution techniques are included with many of the solutions. Description - Self Solving Sudoku - Slice and Dice - Locked Candidates Pointing - Triple Subset - Pair - Locked Candidates Claiming - New York Times Sudoku Hard October 21, 2022 -. The New York Times regularly publishes a number-based puzzle game called NYT Sudoku.

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